Hi y’all I’m working on a problem we have to design a program that takes as input a 9 digit number where no digit appears twice and produces as output an arrangement of the same 9 digits corresponding to the next highest number. So for example if the input is 781623954 the output would be 781624359.
My code below runs infinitely while displaying only a +1 number (for eg if I input 781623954 it will repeat 781623955 9 times then repeat 781623960 9 times). I’ve written my logic for each line below but can’t find where I went wrong. Can anyone let me know which part of my logic is wrong?
#User's input number, define variables user_input= input("write a nine digit number without repeating any digit: ") candidate= int(user_input)+1 found= True #as long as each digit of candidate can be found in user input number... while found: #assign digit to each number in candidate as it #goes through loop for each number in candidate for digit in str(candidate): #what has to happen in order for candidate to be false. if digit not in user_input: found = False #Needs to be false so the loop keeps running? #for loop keeps going for each number in user_input else: found= True #Is this necessary? print("The number is", candidate) #Add one to try the next candidate candidate=candidate+1